MASM --- loop basic

  1. Include Irvine32.inc
  2. .data
  3.     MSG0 byte "enter your number: ",0dh,0ah,0
  4.     MSG1 byte "how many digits: ",0dh,0ah,0
  5.     MSG2 byte "enter sth to halt: ",0dh,0ah,0
  6.     number dword 0
  7.     count dword 0
  8. .code
  9.     main proc
  10.     L0:
  11.     mov edx, offset MSG0        ; display string
  12.     call writestring
  13.     call readint
  14.     mov number, eax
  15.     .if (eax <= 0)
  16.     jmp L3
  17.     .endif
  18.     mov ecx, eax        ; do exact same time as number
  19.     mov ebx, 10         ; divide 10 every time
  20.     mov eax, number
  21.     L1:
  22.     .if ( eax > 0 )
  23.         cdq
  24.         mov ebx, 10
  25.         idiv ebx
  26.         inc count
  27.     LOOP L1
  28.     .else
  29.         jmp L2
  30.     .endif
  31.     L2:
  32.     mov edx, offset MSG1
  33.     call writestring
  34.     mov eax, count
  35.     call writedec
  36.     call crlf
  37.     mov count, 0
  38.     jmp L0
  39.     L3:
  40.     mov edx, offset MSG2
  41.     call writestring
  42.     call crlf
  43. exit
  44. main endp
  45. end main


留言

張貼留言

這個網誌中的熱門文章

Codeforces --- string task

Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it: deletes all the vowels, inserts a character " . " before each consonant, replaces all uppercase consonants with corresponding lowercase ones. Vowels are letters "A", "O", "Y", "E", "U", "I", and the rest are consonants. The program's input is exactly one string, it should return the output as a single string, resulting after the program's processing the initial string. Help Petya cope with this easy task. Input The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from  1  to  100 , inclusive. Output Print the resulting string. It is guaranteed that this string is
閱讀完整內容

Uva 674 ---- coin change

圖片
// coin change #include <iostream> using   namespace  std ; int  main ( ) { int  iCoin [ 7490 ] [ 5 ] ; int  iMoney [ 5 ]   =   {   1 ,  5 ,  10  ,  25 ,  50   } ; int  iAmount, i ,j, iMax ; while   (   cin   >>  iAmount  )      {     iMax  =   - 1 ;        for   (  i = 0   ;  i <= iAmount  ;  i ++   )           iCoin [ i ] [ 0 ]   =   1 ;      for   (  j = 0   ;  j < 5   ;  j ++   )         iCoin [ 0 ] [ j ]   =   1 ;      for   (  i = 1   ;  i <= iAmount  ;  i ++   )                for   (  j = 1   ;  j < 5   ;  j ++   )              {              if   (  i - iMoney [ j ]   >=   0   )                 iCoin [ i ] [ j ]   =   (  iCoin [ i ] [ j - 1 ]   +  iCoin [ i - iMoney [ j ] ] [ j ]   ) ;                  else                 iCoin [ i ] [ j ]   =  iCoin [ i ] [ j - 1 ] ;                                  }      /*          for ( i=0 ; i<iAmount ; i++ )               {
閱讀完整內容

codeforces 271A --- beautiful year

BEAUTIFUL YEAR It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits. Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits. Input The single line contains integer  y   (1000 ≤  y  ≤ 9000)  — the year number. Output Print a single integer — the minimum year number that is strictly larger than  y  and all it's digits are distinct. It is guaranteed that the answer exists. Examples input 1987 output 2013 input 2013 output 2014 #include <iostream> using   namespace  std ; int  iFind  (   int  iIn  ) { int  iFlag ;   int  iBucket [ 10 ] ; for   (   int  i = 0   ;  i < 10   ;  i ++   )     iBucket [ i ]   =   0 ; iFlag  =   0 ; while   (  iIn  )      {      if   (  iBucket [
閱讀完整內容