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MASM --- loop basic

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Include Irvine32 . inc .data     MSG0  byte   "enter your number: " , 0dh , 0ah , 0     MSG1  byte   "how many digits: " , 0dh , 0ah , 0     MSG2  byte   "enter sth to halt: " , 0dh , 0ah , 0     number  dword   0     count  dword   0 . code     main proc     L0 :      mov   edx ,  offset MSG0         ; display string      call  writestring      call  readint      mov  number ,   eax      . if  ( eax  <=  0 )      jmp  L3      . endif      mov   ecx ,   eax          ; do exact same time as number      mov   ebx ,   10           ; d...
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JAVA 7.8

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import   java.util.Scanner ; public   class  Sumarray  {      public   static   void  main ( String [ ]  args )   {      int [ ]  iBucket  =   new   int [ 10 ] ;      double   [ ]  dBucket  =   new   double [ 10 ] ;     Scanner input  =    new  Scanner ( System . in ) ;      int  i ;      for   (  i = 0   ;  i < 10   ;  i ++   )          {         iBucket [ i ]   =  input. nextInt ( ) ;         dBucket [ i ]   =  input. nextDouble ( ) ;          }      System . out . println ( sum  ( iBucket ) ) ;      System . out . println ( sum  ( dBucket ) ) ;   ...
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codeforces 271A --- beautiful year

BEAUTIFUL YEAR It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits. Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits. Input The single line contains integer  y   (1000 ≤  y  ≤ 9000)  — the year number. Output Print a single integer — the minimum year number that is strictly larger than  y  and all it's digits are distinct. It is guaranteed that the answer exists. Examples input 1987 output 2013 input 2013 output 2014 #include <iostream> using   namespace  std ; int  iFind  (   int  iIn  ) { int  iFlag ;   int  iBucket [ 10 ] ; for   (   int  i = 0   ;  i < 10   ;  i ++ ...
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